document.write( "Question 212985This question is from textbook Geometry for the ejoyment and challenge
\n" ); document.write( ": the supplement of an angle is four times the complement of the angle. Find the measure of the complement. \n" ); document.write( "
Algebra.Com's Answer #160898 by MathTherapy(10552)\"\" \"About 
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the supplement of an angle is four times the complement of the angle. Find the measure of the complement.\r
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\n" ); document.write( "\n" ); document.write( "Let the angle be A
\n" ); document.write( "Then the supplement of the angle is (180 - A), and the complement of the angle is (90 - A)\r
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\n" ); document.write( "\n" ); document.write( "Since the supplement is four times the complement, then we'll have:\r
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\n" ); document.write( "\n" ); document.write( "180 - A = 4(90 - A)\r
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\n" ); document.write( "\n" ); document.write( "180 - A = 360 - 4A\r
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\n" ); document.write( "\n" ); document.write( "3A = 180\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+180%2F3+=+60%5Eo\"\r
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\n" ); document.write( "\n" ); document.write( "Since A, or the angle is \"60%5Eo\", then its complement is 90 - 60 = \"highlight_green%2830%5Eo%29\" \r
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\n" ); document.write( "\n" ); document.write( "Angle = \"60%5Eo\". Therefore, its supplement = \"120%5Eo\" (180 - 60)\r
\n" ); document.write( "\n" ); document.write( "Also, its complement is \"30%5Eo\" (90 - 60)\r
\n" ); document.write( "\n" ); document.write( "So, since its supplement is equal to 4 times its complement, then:\r
\n" ); document.write( "\n" ); document.write( "\"120%5Eo+=+4%2830%29\", or, \"120%5Eo+=+120%5Eo\" ---TRUE--- \r
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