document.write( "Question 212989: 3^2x+(3^x)-2=0?
\n" ); document.write( "My professor gave us a hint and said to change out the 3x for a u..? I think that confused me. I have tried to substitute the 3x for a u. Ex: 3^2x+u-2=0 but that does not make sense so i tried to use u(2-2)=0? I am so confused please help :)
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #160897 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Here's another hint: we can rewrite \"3%5E%282x%29\" as \"3%5E%28x%2A2%29\" and \"%283%5Ex%29%5E2\". In other words, \"3%5E%282x%29=%283%5Ex%29%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So \"3%5E%282x%29%2B3%5Ex-2=0\" transforms into \"%283%5Ex%29%5E2%2B3%5Ex-2=0\". Now do you see how the substitution \"u=3%5Ex\" will help? If not, then just repost or ask me.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "---------------------------------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "New stuff....\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%5E%282x%29%2B3%5Ex-2=0\" Start with the given equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%283%5Ex%29%5E2%2B3%5Ex-2=0\" Rewrite \"3%5E%282x%29\" as \"%283%5Ex%29%5E2\" (see above).\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now let \"u=3%5Ex\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"u%5E2%2Bu-2=0\" Replace each \"3%5Ex\" with 'u'\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Take note that we now have a much simpler quadratic to solve.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"u%5E2%2Bu-2\" is in the form of \"Au%5E2%2BBu%2BC\" where \"A=1\", \"B=1\", and \"C=-2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"u\":\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"u+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"u+=+%28-%281%29+%2B-+sqrt%28+%281%29%5E2-4%281%29%28-2%29+%29%29%2F%282%281%29%29\" Plug in \"A=1\", \"B=1\", and \"C=-2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"u+=+%28-1+%2B-+sqrt%28+1-4%281%29%28-2%29+%29%29%2F%282%281%29%29\" Square \"1\" to get \"1\". \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"u+=+%28-1+%2B-+sqrt%28+1--8+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%28-2%29\" to get \"-8\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"u+=+%28-1+%2B-+sqrt%28+1%2B8+%29%29%2F%282%281%29%29\" Rewrite \"sqrt%281--8%29\" as \"sqrt%281%2B8%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"u+=+%28-1+%2B-+sqrt%28+9+%29%29%2F%282%281%29%29\" Add \"1\" to \"8\" to get \"9\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"u+=+%28-1+%2B-+sqrt%28+9+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"u+=+%28-1+%2B-+3%29%2F%282%29\" Take the square root of \"9\" to get \"3\". \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"u+=+%28-1+%2B+3%29%2F%282%29\" or \"u+=+%28-1+-+3%29%2F%282%29\" Break up the expression. \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"u+=+%282%29%2F%282%29\" or \"u+=++%28-4%29%2F%282%29\" Combine like terms. \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"u+=+1\" or \"u+=+-2\" Simplify. \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the solutions (in terms of 'u') are \"u+=+1\" or \"u+=+-2\" \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "However, we want the solutions in terms of 'x'.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let's find the solution of 'x' that corresponds to \"u=1\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"u=3%5Ex\" Go back to the substitution equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1=3%5Ex\" Plug in \"u=1\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%5E0=3%5Ex\" Rewrite \"1\" as \"3%5E0\". Note: ANY number (except 0) to the 0th power is 1.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since the bases are equal, the exponents are equal. So \"0=x\" or \"x=0\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the first solution is \"x=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-----------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let's find the solution of 'x' that corresponds to \"u=-2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"u=3%5Ex\" Go back to the substitution equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"-2=3%5Ex\" Plug in \"u=-2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%28-2%29%29=log%2810%2C%283%5Ex%29%29\" Take the log of both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since you CANNOT take the log of a negative number, this means that we cannot continue\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So there isn't a corresponding solution of 'x' to \"u=-2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "============================================================\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the only solution is \"x=0\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%5E%282x%29%2B3%5Ex-2=0\" Start with the given equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%5E%282%2A0%29%2B3%5E0-2=0\" Plug in \"x=0\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%5E0%2B3%5E0-2=0\" Multiply\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1%2B1-2=0\" Raise 3 to the zeroth power to get 1.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2-2=0\" Add\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"0=0\" Subtract.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since the equation is true, the solution \"x=0\" is verified.
\n" ); document.write( "
\n" );