document.write( "Question 212950: y = 2^x x = 2^y\r
\n" ); document.write( "\n" ); document.write( "Evaluate the exponential equation for three positive values of x, three negative values of x, and x =0. Transform the second expression into the equivalent logarithmic equation; and evaluate the logarithmic equation for three values of x that ar greater than 1, three values of x that are between 0 and 1, and at x = 1. Use the resulting ordered pairs to plot the graph of each function.\r
\n" ); document.write( "\n" ); document.write( "On the first equation I got y = 2^x\r
\n" ); document.write( "\n" ); document.write( "X Y 3 positives of x
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\n" ); document.write( "3 8\r
\n" ); document.write( "\n" ); document.write( "X Y 3 negatives of x
\n" ); document.write( "-1 -2
\n" ); document.write( "-2 -4
\n" ); document.write( "-3 -8\r
\n" ); document.write( "\n" ); document.write( "X Y x = 0
\n" ); document.write( "0 2\r
\n" ); document.write( "\n" ); document.write( "I do not under stand the second part of this equation. Is the first part correct?\r
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Algebra.Com's Answer #160876 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
y = 2^x x = 2^y
\n" ); document.write( "Evaluate the exponential equation for three positive values of x, three negative values of x, and x =0. Transform the second expression into the equivalent logarithmic equation; and evaluate the logarithmic equation for three values of x that ar greater than 1, three values of x that are between 0 and 1, and at x = 1. Use the resulting ordered pairs to plot the graph of each function.
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\n" ); document.write( "FIRST EQUATION
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\n" ); document.write( "\"y+=+2%5Ex\"
\n" ); document.write( "x is the exponent, 2 is the base.
\n" ); document.write( "-----
\n" ); document.write( "when x is positive:
\n" ); document.write( "\"2%5E1+=+2\"
\n" ); document.write( "\"2%5E2+=+4\"
\n" ); document.write( "\"2%5E3+=+8\"
\n" ); document.write( "-----
\n" ); document.write( "when x is negative:
\n" ); document.write( "\"2%5E%28-1%29+=+1%2F%282%5E1%29+=+1%2F2\"
\n" ); document.write( "\"2%5E%28-2%29+=+1%2F%282%5E2%29+=+1%2F4\"
\n" ); document.write( "\"2%5E%28-3%29+=+1%2F%282%5E3%29+=+1%2F8\"
\n" ); document.write( "-----
\n" ); document.write( "graph of y = 2^x is shown below:
\n" ); document.write( "\"graph+%28300%2C300%2C-10%2C10%2C-10%2C10%2C2%5Ex%29\"
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\n" ); document.write( "SECOND EQUATION
\n" ); document.write( "-----
\n" ); document.write( "\"x+=+2%5Ey\"
\n" ); document.write( "y is the exponent, 2 is the base.
\n" ); document.write( "-----
\n" ); document.write( "when y is positive:
\n" ); document.write( "\"2%5E1+=+2\"
\n" ); document.write( "\"2%5E2+=+4\"
\n" ); document.write( "\"2%5E3+=+8\"
\n" ); document.write( "-----
\n" ); document.write( "when y is negative:
\n" ); document.write( "\"2%5E%28-1%29+=+1%2F%282%5E1%29+=+1%2F2\"
\n" ); document.write( "\"2%5E%28-2%29+=+1%2F%282%5E2%29+=+1%2F4\"
\n" ); document.write( "\"2%5E%28-3%29+=+1%2F%282%5E3%29+=+1%2F8\"
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\n" ); document.write( "You cannot graph this directly since the graphs are set up so that the independent variable is x and the dependent variable is y.
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\n" ); document.write( "In order to graph this, you have to solve for y.
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\n" ); document.write( "Your equation is:
\n" ); document.write( "\"x+=+2%5Ey\"
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\n" ); document.write( "The basic definition of an exponential equation is:
\n" ); document.write( "\"y+=+b%5Ex\" if and only if \"x+=+log%28b%2Cy%29\"
\n" ); document.write( "When you reverse the x and y like we have in this second form of the exponential equation, then the basic definition becomes:
\n" ); document.write( "\"x+=+b%5Ey\" if and only if \"y+=+log%28b%2Cx%29\"
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\n" ); document.write( "Your equation is:
\n" ); document.write( "\"x+=+2%5Ey\"
\n" ); document.write( "-----
\n" ); document.write( "By the basic definition of exponents, \"x+=+2%5Ey\" if and only if \"y+=+log%282%2Cx%29\"
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\n" ); document.write( "The graph of \"y+=+log%282%2Cx%29\" is shown below:
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\n" ); document.write( "\"graph+%28300%2C300%2C-10%2C10%2C-10%2C10%2Clog%282%2Cx%29%29\"
\n" ); document.write( "-----
\n" ); document.write( "\"y+=+log%282%2Cx%29\" is the inverse equation of \"y+=+2%5Ex\"
\n" ); document.write( "You derive the inverse equation by doing exactly what they are asking you to do when they showed you the two equations.
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\n" ); document.write( "In order to find the inverse equation of \"y+=+2%5Ex\" you would do the following:
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\n" ); document.write( "Solve for x:
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\n" ); document.write( "By the basic definition of exponents, \"y+=+2%5Ex\" if and only if \"x+=+log%282%2Cy%29\"
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\n" ); document.write( "You have just solved for x by just applying the basic definition of exponents.
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\n" ); document.write( "You have:
\n" ); document.write( "\"x+=+log%282%2Cy%29\"
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\n" ); document.write( "Next you transpose the x and the y in the equation.
\n" ); document.write( "Your equation becomes:
\n" ); document.write( "\"y+=+log%282%2Cx%29\"
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\n" ); document.write( "\"y+=+log%282%2Cx%29\" is the inverse equation of \"y+=+2%5Ex\"
\n" ); document.write( "-----
\n" ); document.write( "You have just derived the inverse equation of \"y+=+2%5Ex\". That equation is \"y+=+log%282%2Cx%29\"
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\n" ); document.write( "The inverse equation is the reflection of the normal equation about the line y = x.
\n" ); document.write( "The following graph shows the normal equation of \"y+=+2%5Ex\" and the inverse equation of \"y+=+log%282%2Cx%29\" and the line \"y+=+x\"
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\n" ); document.write( "\"graph+%28300%2C300%2C-10%2C10%2C-10%2C10%2C2%5Ex%2Clog%282%2Cx%29%2Cx%29\"
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\n" ); document.write( "If you draw a perpendicular line anywhere through the line y = x, the intersection of that line through \"y+=+2%5Ex\" will be (a,b), and the intersection of that line through \"y+=+log%282%2Cx%29\" will be (b,a).
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\n" ); document.write( "for example:
\n" ); document.write( "when x = 2, \"y+=+2%5E2\" = 4 so the coordinates are (2,4)
\n" ); document.write( "when x = 4, \"y+=+log%282%2C4%29\" = 2 so the coordinates are (4,2)
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\n" ); document.write( "The equation of the line perpendicular to the line y = x and passing through the points (2,4) and (4,2) is y = -x + 6.
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\n" ); document.write( "Adding that line to the graph of the 3 equations yields the following:
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\n" ); document.write( "\"graph+%28300%2C300%2C-10%2C10%2C-10%2C10%2C2%5Ex%2Clog%282%2Cx%29%2Cx%2C-x%2B6%29\"
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\n" ); document.write( "As you can see, the two points intersecting with the line perpendicular to the line y = x are the same distance from that line making the two graphs symmetric to each other about the line y = x.
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