document.write( "Question 212932: I have solved the first part of the problem but need help with the second!\r
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\n" ); document.write( "\n" ); document.write( "Assume that a surveyor stands at the top of a mountain that is “h” feet tall. If the distance (in feet) that he can see is defined by d = 3200.2 SQRT(h), then answer the following. (a) How far can the surveyor see from the top of a 2000-foot mountain? (b) How tall is the mountain, if the surveyor can see 15 miles? (Note: 1 mile equals 5280 feet.)\r
\n" ); document.write( "\n" ); document.write( "d=3200.2SQRT2000
\n" ); document.write( "d=3200.2(44.72
\n" ); document.write( "d=143117.29 ft\r
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\n" ); document.write( "\n" ); document.write( "Thanks for the help!
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Algebra.Com's Answer #160874 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Ok on part 1 of the problem!
\n" ); document.write( "Part 2.
\n" ); document.write( "\"d+=+3200.2sqrt%28h%29\" Substitute h = 15mi.(5280ft/mi.) = 79200feet.
\n" ); document.write( "\"79200+=+3200.2sqrt%28h%29\" Divide both sides by 3200.2
\n" ); document.write( "\"24.75+=+sqrt%28h%29\" Square both sides.
\n" ); document.write( "\"612.486+=+h\"
\n" ); document.write( "The mountain is 612.5 feet tall.
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