document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=212940>Question 212940</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I cant figure out how to set up this problem:<BR>\n" );
document.write( "Find three consecutive odd integers whose sum is between 135 and 147<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #160858 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=160858\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = first odd integer<BR>\n" );
document.write( "x+2 = second <BR>\n" );
document.write( "x+4 = third\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The sum of these integers (add them up!) is 3x+6.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "You must find x such that <BR>\n" );
document.write( "135<3x+6<147\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Bubtract 6 from the center, left, and right parts of this inequality:<BR>\n" );
document.write( "135-6<3x+6-6<147-6<BR>\n" );
document.write( "129<3x<141\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Divide by 3:<BR>\n" );
document.write( "129/3 <x<141/3<BR>\n" );
document.write( "43< x< 47\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Now remember, x has to be an ODD NUMBER, BETWEEN (not including!) 43 and 47!!\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "So the first number must be x=45 <BR>\n" );
document.write( "The second number must then be x+2=  47<BR>\n" );
document.write( "The third number is x+4 = 49\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The solution:   45, 47, 49.<BR>\n" );
document.write( "The sum is :     141\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "R^2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Dr. Robert J. Rapalje, Retired<BR>\n" );
document.write( "Seminole Community College<BR>\n" );
document.write( "Altamonte Springs Campus<BR>\n" );
document.write( "Florida  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );