document.write( "Question 29256: A freight train leaves Kansas and travels due west. A passenger train departs at exactly the same time on a parallel track and travels due east at a speed that is twice the speed of the freight train. After 7 hours the trains are 945 miles apart. How fast is each train traveling? \n" ); document.write( "
Algebra.Com's Answer #16084 by venugopalramana(3286)\"\" \"About 
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A freight train leaves Kansas and travels due west. A passenger train departs at exactly the same time on a parallel track and travels due east at a speed that is twice the speed of the freight train. After 7 hours the trains are 945 miles apart. How fast is each train traveling?
\n" ); document.write( "TRAINS ARE TRAVELLING IN OPPOSITE DIRECTIONS..SO THEIR RELATVE SPEED =SUM OF THEIR INDIVIDUAL SPEEDS
\n" ); document.write( "SPEED OF ONE TRAIN IS X MPH....SAY..SECOND TRAIN SPEED =2X..MPH....SO
\n" ); document.write( "RELATIVE SPEED =X+2X=3X...MPH
\n" ); document.write( "TIME =7 HRS
\n" ); document.write( "INTIAL DISTANCE BETWEEN THEM =0
\n" ); document.write( "FINAL DOISTANCE BETWEEN THEM =945 MILES
\n" ); document.write( "SO DISTANCE CHANGEW =945-0=945 MILES..HENCE
\n" ); document.write( "945 =7*3X=21X
\n" ); document.write( "X=945/21=45 MPH
\n" ); document.write( "SO THE 2 TRAINS TRAVELLED AT 45 AND 90 MPH.
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