document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=212911>Question 212911</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Twice the difference of a number and 6 is equal to three times the sum of the number and 4.  Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #160828 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=160828\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the number\r<BR>\n" );
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document.write( "2(x-6)=3(x+4)<BR>\n" );
document.write( "2x-12=3x+12\r<BR>\n" );
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document.write( "Subtract 2x from each side to get all the variables on the right side:<BR>\n" );
document.write( "2x-2x -12 = 3x-2x +12<BR>\n" );
document.write( "-12 =X+12\r<BR>\n" );
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document.write( "Subtract 12 from each side to get all the number terms on the OPPOSITE side.<BR>\n" );
document.write( "-12-12=x+12-12<BR>\n" );
document.write( "-24 = x\r<BR>\n" );
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document.write( "R^2 </SPAN>\n" );
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