document.write( "Question 212894: blake has a total of $1200 to invest into 2 accounts. one account earns 6% simple interest and the other earns 7% simple interest. how much should be invested into both accounts to earn exactly $79 at the end of year 1?
\n" ); document.write( "? 6% account ? 7% account \n" ); document.write( "

Algebra.Com's Answer #160802 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"a\"$ = amount invested in 6% account
\n" ); document.write( "Let $\"b\"$ = amount invested in 7% account
\n" ); document.write( "given:
\n" ); document.write( "(1) $\"a+%2B+b+=+1200\"$
\n" ); document.write( "(2) $\".06a+%2B+.07b+=+79\"$
\n" ); document.write( "Multiply both sides of (2) by $\"100\"$
\n" ); document.write( "(1) $\"a+%2B+b+=+1200\"$
\n" ); document.write( "(2) $\"6a+%2B+7b+=+7900\"$
\n" ); document.write( "Multiply both sides of (1) by $\"6\"$ and
\n" ); document.write( "subtract (1) from (2)
\n" ); document.write( "(2) $\"6a+%2B+7b+=+7900\"$
\n" ); document.write( "(1) $\"-6a+-+6b+=+-7200\"$
\n" ); document.write( " $\"b+=+700\"$
\n" ); document.write( "And, since $\"a+%2B+b+=+1200\"$ ,
\n" ); document.write( " $\"a+=+1200+-+700\"$
\n" ); document.write( " $\"a+=+500\"$
\n" ); document.write( "$500 should be invested @ 6%
\n" ); document.write( "$700 should be invested @ 7%\r
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