document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=212873>Question 212873</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve. Where appropriate, include approximations to the nearest thousandth. If no solution exists, state this.\r<BR>\n" );
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document.write( "ln (x - 5) + ln (x + 4) = ln 36\r<BR>\n" );
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document.write( "So I thought I remembered how to do these but I guess not. I tried to google some examples but still can't figure it out. Can someone help it would be greatly appreciated.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #160791 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrapro18><B>algebrapro18(249)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrapro18><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=160791\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well to do this problem we need to use 2 properties of ln.  <br>\r<BR>\n" );
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document.write( "1.  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ln%28xy%29+=+ln%28x%29+%2B+ln%28y%29 ALIGN=MIDDLE  ALT=\"ln%28xy%29+=+ln%28x%29+%2B+ln%28y%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "2.  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=e%5E%28ln%28x%29%29+=+x ALIGN=MIDDLE  ALT=\"e%5E%28ln%28x%29%29+=+x\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br>\r<BR>\n" );
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document.write( "Now that we have those out of the way we can solve the equation.  First we need to use property 1 on the equation.  We get:<br>\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ln+%28x+-+5%29+%2B+ln+%28x+%2B+4%29+=+ln+36 ALIGN=MIDDLE  ALT=\"ln+%28x+-+5%29+%2B+ln+%28x+%2B+4%29+=+ln+36\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ln%28%28x-5%29%28x%2B4%29%29+=+ln+36 ALIGN=MIDDLE  ALT=\"ln%28%28x-5%29%28x%2B4%29%29+=+ln+36\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br>\r<BR>\n" );
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document.write( "Now we use propterty 2 by raising both sides to the e power.  <br>\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ln%28%28x-5%29%28x%2B4%29%29+=+ln+36 ALIGN=MIDDLE  ALT=\"ln%28%28x-5%29%28x%2B4%29%29+=+ln+36\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=e%5E%28ln%28%28x-5%29%28x%2B4%29%29%29+=+e%5E%28ln+36%29 ALIGN=MIDDLE  ALT=\"e%5E%28ln%28%28x-5%29%28x%2B4%29%29%29+=+e%5E%28ln+36%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-5%29%28x%2B4%29+=+36 ALIGN=MIDDLE  ALT=\"%28x-5%29%28x%2B4%29+=+36\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br>\r<BR>\n" );
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document.write( "And now we solve the quadratic equation.<br>\r<BR>\n" );
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document.write( "(x-5)(x+4) = 36<BR>\n" );
document.write( "x^2-x-20 = 36<BR>\n" );
document.write( "x^2-x-56 = 0<BR>\n" );
document.write( "(x-8)(x+7)=0<br>\r<BR>\n" );
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document.write( "so x = -7 and x = 8.  If you check those solutions you will find that indeed they work.   </SPAN>\n" );
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