document.write( "Question 212802: write an equation of the tangent function with period 3pi/8, phase shift -pi/5, and vertical shift -2\r
\n" ); document.write( "\n" ); document.write( "a)y=tan(8x/3 - 8pi/15)-2
\n" ); document.write( "b)y=tan(8x/3 + 8pi/15)-2
\n" ); document.write( "c)y=tan(16x/3 + 3pi/80)-2
\n" ); document.write( "d)y=tan(8x/3 - 3pi/40)-2
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Algebra.Com's Answer #160790 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
Using a general form of \"y+=+tan%28B%28x-D%29%29+%2B+C\" where B = (the natural period of tan)/(period of this function), D is the phase shift and C is the vertical shift, we want an equation where \"B+=+%28pi%29%2F%28%283%2Api%29%2F8%29+=+8%2F3\", \"D+=+-%28pi%2F5%29\" and C = -2. We want an equation that looks like:
\n" ); document.write( "\"y+=+tan%28%288%2F3%29%28x+-+%28-%28pi%2F5%29%29%29%29+%2B+%28-2%29\"
\n" ); document.write( "or
\n" ); document.write( "\"y+=+tan%28%288%2F3%29%28x+%2B+pi%2F5%29%29+-+2\"
\n" ); document.write( "None of the answers look this this. But if we multiply out the argument of tan we get:
\n" ); document.write( "\"y+=+tan%28%288%2F3%29x+%2B+%288%2Api%29%2F15%29+-+2\"
\n" ); document.write( "which matches answer \"b\"
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