document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=212852>Question 212852</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I was wondering how I would punch this into the calculator to find the answer? Please help!\r<BR>\n" );
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document.write( "Solve for x. Round to the nearest ten-thousandth.\r<BR>\n" );
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document.write( "log (225x2) = 3.456  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #160768 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=160768\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> do you mean log(225 x^2) = 3.456 ...\r<BR>\n" );
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document.write( "first, divide by 2 ___ this means taking the square root of the quantity in the log parentheses\r<BR>\n" );
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document.write( "log(15 x) = 1.728\r<BR>\n" );
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document.write( "next, take the antilog or inverse log or log^-1 ___ different calculators have different keys\r<BR>\n" );
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document.write( "15 x = 10^1.728 = 53.456436...\r<BR>\n" );
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document.write( "next, divide by 15 ___ x = 3.5638\r<BR>\n" );
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document.write( "because the x is squared in the original equation, -3.5638 is also a solution </SPAN>\n" );
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