document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=212838>Question 212838</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find length and width of rectangle if perimeter is 50cm, when the sides are (4a-3)cm and (2a+7)cm.<BR>\n" );
document.write( "Thank you so much for your help.<BR>\n" );
document.write( "From Pure Math grade 10 workbook </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #160755 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=160755\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do you find length and width of rectangle if perimeter is 50cm, when the sides are (4a-3)cm and (2a+7)cm.<BR>\n" );
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document.write( "Let the width be 4a-3; let the length be 2a+7<BR>\n" );
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document.write( "Perimeter = 2(L + W)<BR>\n" );
document.write( "50 = 2(4a-3+2a+7)<BR>\n" );
document.write( "25 = 6a+4<BR>\n" );
document.write( "6a = 21<BR>\n" );
document.write( "a = 7/2<BR>\n" );
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document.write( "width = 4(7/2)-3 = 11 cm<BR>\n" );
document.write( "length = 2(7/2)-3 = 4 cm<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );