document.write( "Question 212816: the sum of two intergers is 10. Three times the larger interger is three less than eight times the smaller integer. Find the integers. \n" ); document.write( "

Algebra.Com's Answer #160736 by Earlsdon(6294) $\"\"$ $\"About$

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Let the larger integer be a and the smaller integer, b, then:
\n" ); document.write( "1) a+b = 10 \"The sum of two integers is 10.\"
\n" ); document.write( "2) 3a = 8b-3 \"Three times the larger...is three less than eight times the smaller...\"
\n" ); document.write( "Rewrite equation 1 as a = 10-b and substitute into equation 2, then solve for b.
\n" ); document.write( "3(10-b) = 8b-3 Expand the left side.
\n" ); document.write( "30-3b = 8b-3 Add 3b to both sides.
\n" ); document.write( "30 = 11b-3 Add 3 to both sides.
\n" ); document.write( "33 = 11b Finally, divide both sides by 11.
\n" ); document.write( "3 = b and a = 10-3 = 7.
\n" ); document.write( "The two integers are:
\n" ); document.write( "7 and 3 \n" ); document.write( "

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