document.write( "Question 211987: a picture is 4 inches longer then wide. it a 1 inch frame is put on and the area is increased by 48 square inches. whats the dimensions of the picture \n" ); document.write( "
Algebra.Com's Answer #160731 by ankor@dixie-net.com(22740)\"\" \"About 
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\"a picture is 4 inches longer than it's wide.\"
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\n" ); document.write( "Let x = the width of the picture
\n" ); document.write( "then
\n" ); document.write( "(x+4) = the length
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\n" ); document.write( "\"if a 1 inch frame is put on, the area is increased by 48 square inches.\"
\n" ); document.write( "(x+4)+ 2 =
\n" ); document.write( "(x+6) = overall length
\n" ); document.write( "and
\n" ); document.write( "(x+2) = overall width
\n" ); document.write( ":
\n" ); document.write( " \"what's the dimensions of the picture\"
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\n" ); document.write( "Overall area - picture area = 48 sq/in
\n" ); document.write( ":
\n" ); document.write( "(x+6)(x+2) - x(x+4) = 48
\n" ); document.write( "FOIL
\n" ); document.write( "x^2 + 2x + 6x + 12 - (x^2 + 4x) = 48
\n" ); document.write( "x^2 + 8x + 12 - x^2 - 4x = 48
\n" ); document.write( "x^2 - x^2 + 8x - 4x = 48 - 12
\n" ); document.write( "4x = 36
\n" ); document.write( "x = \"36%2F4\"
\n" ); document.write( "x = 9 in is width of the picture
\n" ); document.write( "and
\n" ); document.write( "9 + 4 = 13 in is the length
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\n" ); document.write( "Check solution:
\n" ); document.write( "15*11 - 13*9 =
\n" ); document.write( "165 - 117 = 48 \n" ); document.write( "
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