document.write( "Question 212787: The period (the time required for one complete swing) of a simple pendulum varies directly as the square root of its legnth. If a pendulum 12 feet long has a period of 4 seconds, find the period of a pendulum 3 feet long. \n" ); document.write( "

Algebra.Com's Answer #160714 by scott8148(6628) $\"\"$ $\"About$

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\"The period (the time required for one complete swing) of a simple pendulum varies directly as the square root of its legnth\"
\n" ); document.write( "___ P = k sqrt(L)\r
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\n" ); document.write( "\n" ); document.write( "4 = k sqrt(12)\r
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\n" ); document.write( "\n" ); document.write( "4 / sqrt(12) = k ___ 2 / sqrt(3) = k ___ 2 sqrt(3) / 3 = k\r
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\n" ); document.write( "\n" ); document.write( "for a 3ft pendulum ___ P = k sqrt(3) = [2 sqrt(3) / 3] sqrt(3) = 2 \n" ); document.write( "

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