document.write( "Question 212773: need to find the slope of line containing points\r
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Algebra.Com's Answer #160694 by drj(1380)\"\" \"About 
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need to find the slope of line containing points\r
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\n" ); document.write( "\n" ); document.write( "However, here are the steps showing you how you can check your work with one of the points.\r
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\n" ); document.write( "\n" ); document.write( "Step 1. The slope of the line m is given as\r
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\n" ); document.write( "\n" ); document.write( "\"+m=%28y2-y1%29%2F%28x2-x1%29\"\r
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\n" ); document.write( "\n" ); document.write( "where for our example is x1=2, y1=0, x2=3 and y2=-2 (think of \"slope=rise%2Frun\"). You can choose the points the other way around but be consistent with the x and y coordinates. You will get the same result.\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Substituting the above values in the slope equation gives\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28-2-0%29%2F%283-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=-2%2F1\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=-2\"\r
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\n" ); document.write( "\n" ); document.write( "Step 3. The slope is calculated as -2 or m=-2\r
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\n" ); document.write( "\n" ); document.write( "Step 4. Now use the slope equation of step 1 and choose one of the given points. I'll choose point (3,-2). Letting y=y2 and x=x2 and substituting m=-3 in the slope equation given as,\r
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\n" ); document.write( "\n" ); document.write( "\"+m=%28y2-y1%29%2F%28x2-x1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"+-2=%28y-%28-2%29%29%2F%28x-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"+-2=%28y%2B2%29%2F%28x-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 5. Multiply both sides of equation by x-3 to get rid of denomination found on the right side of the equation\r
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\n" ); document.write( "\n" ); document.write( "\"+-2%28x-3%29=%28x-3%29%28y%2B2%29%2F%28x-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"+-2%28x-3%29=y%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "Step 6. Now simplify and put the above equation into slope-intercept form.\r
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\n" ); document.write( "\n" ); document.write( "\"-2x%2B6=y%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "Subtract 2 from both sides of the equation\r
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\n" ); document.write( "\n" ); document.write( "\"-2x%2B6-2=y%2B2-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"-2x%2B4=y\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=-2x%2B4\" ANSWER in slope-intercept form. m=-2 and y-intercept=4\r
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\n" ); document.write( "\n" ); document.write( "Step 7. See if the other point (2,0) or x=2 and y=0 satisfies this equation\r
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\n" ); document.write( "\n" ); document.write( "\"y=-2x%2B4\"\r
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\n" ); document.write( "\n" ); document.write( "\"0=-2%2A2%2B4\"\r
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\n" ); document.write( "\n" ); document.write( "\"0=0\" So the point (2,0) satisfies the equation and is on the line. In other words, you can use the other point to check your work.\r
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\n" ); document.write( "\n" ); document.write( "Note; above equation can be also be transform into standard form as\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2By=4\"\r
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\n" ); document.write( "\n" ); document.write( "See graph below to check the above steps.\r
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"2+x+%2B+1+y+=+4\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+-2%2F1\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 4/2 = 2.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 4/1 = 4.
  • Slope is -2/1 = -2.
  • Equation in slope-intercept form: y=-2*x+4.
\"graph%28+500%2C+500%2C+2-8%2C+2%2B8%2C+4-8%2C+4%2B8%2C+-2%2Ax%2B4+%29+\"\n" ); document.write( "

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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful. \r
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\n" ); document.write( "And good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J
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