document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=212723>Question 212723</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the measure of a supplement of angle R where angle R is equal to 6x+15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #160639 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=160639\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the measure of a supplement of angle R where angle R is equal to 6x+15<BR>\n" );
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document.write( "If two angles are supplementary, the sum of the two angles = 180<BR>\n" );
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document.write( "Therefore, the<BR>\n" );
document.write( "\"supplement of angle R\" = 180 - (6x+15)<BR>\n" );
document.write( "\"supplement of angle R\" = 180 - 6x -15<BR>\n" );
document.write( "\"supplement of angle R\" = 165 - 6x\r<BR>\n" );
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