document.write( "Question 212371: A police car passed a truck which was traveling at 80km/h and 6 minutes later was 3 km ahead of the truck. What was the speed of the police car? \n" ); document.write( "

Algebra.Com's Answer #160629 by Theo(13342) $\"\"$ $\"About$

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Police Car was traveling at 110 km/h.
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\n" ); document.write( "Rate * Time = Distance
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\n" ); document.write( "Time = 6 minutes / 60 = .1 hours
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\n" ); document.write( "Truck Rate = 80 km/h
\n" ); document.write( "Truck Time = .1 hours
\n" ); document.write( "Truck Distance = 80 * .1 = 8 km
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\n" ); document.write( "Police Car Rate = x km/h
\n" ); document.write( "Police Car Time = .1 hours
\n" ); document.write( "Police Car Distance = 11 km
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\n" ); document.write( "11 km is 3 more km than the truck because the police car traveled 3 km more than the truck in the same amount of time.
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\n" ); document.write( "Rate * Time = Distance
\n" ); document.write( "For the Police Car, this formula becomes:
\n" ); document.write( "x * .1 = 11
\n" ); document.write( "Solve for x to get:
\n" ); document.write( "x = 110 km
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\n" ); document.write( "Police Car was traveling at 110 km/h.
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\n" ); document.write( "Both traveled for 6 minutes
\n" ); document.write( "The Truck traveled 8 kilometers at 80 km/h
\n" ); document.write( "The Police Car traveled 11 kilometers at 110 km/h
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\n" ); document.write( "6 minutes = .1 hours
\n" ); document.write( ".1 * 80 = 8
\n" ); document.write( ".1 * 110 = 11
\n" ); document.write( "11 - 8 = 3
\n" ); document.write( "The police Car was 3 miles ahead of the truck after 6 minutes.
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