document.write( "Question 29229: can someone show me how to solve by addition method...
\n" ); document.write( "2x=2-y
\n" ); document.write( "3x+y=-1
\n" ); document.write( "

Algebra.Com's Answer #16062 by sdmmadam@yahoo.com(530)\"\" \"About 
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can someone show me how to solve by addition method...
\n" ); document.write( "2x=2-y ----(1)
\n" ); document.write( "3x+y=-1 ---(2)
\n" ); document.write( "Rewriting (1)
\n" ); document.write( "(LHS = RHS same as RHS = LHS)
\n" ); document.write( "(Tom's age = Jack's age same as Jack's age = Tom's age)
\n" ); document.write( "2-y = 2x ---(3)
\n" ); document.write( "(2) +(3)
\n" ); document.write( "(3x+y)+(2-y)=(-1)+(2x)
\n" ); document.write( "3x+2+(y-y) =-1+2x
\n" ); document.write( "3x+2+0 = -1+2x
\n" ); document.write( "(3x-2x) = -1-2 (grouping like terms, change side then change sign)
\n" ); document.write( "x = -3
\n" ); document.write( "Put x=-3 in (2)
\n" ); document.write( "3x+y=-1
\n" ); document.write( "3X(-3)+y = -1
\n" ); document.write( "-9+y =-1
\n" ); document.write( "y =-1+9 = 8
\n" ); document.write( "Answer: x=-3,y=8
\n" ); document.write( "Verification: x=-3,y=8 in (1)
\n" ); document.write( "LHS = 2x= =2X(-3) = -6 = 2-8 = 2-y = RHS
\n" ); document.write( "Therefore our values are correct.\r
\n" ); document.write( "\n" ); document.write( "Note: Addition includes subtraction.
\n" ); document.write( "Observe that (1) is 2x+y = 2 ---(*) (bringing y from the right to the left)
\n" ); document.write( "And (2) is 3x+y=-1 ---(2)\r
\n" ); document.write( "\n" ); document.write( "(*)-(2) implies (2x-3x)+0 = 2-(-1)
\n" ); document.write( "-x = 3 giving x=-3
\n" ); document.write( "and then proceed as above\r
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