document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=212375>Question 212375</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two bicyclists started at the same time from towns 84km apart and rode toward each other. Because one of them rode downhill, his speed was twice as great as that of the other. Find both speeds if they meet after two hours. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #160615 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=160615\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=dist traveled by the slower bike.<BR>\n" );
document.write( "2x+x=84<BR>\n" );
document.write( "3x=84<BR>\n" );
document.write( "x=28 mi <BR>\n" );
document.write( "28mi/2h=14mi/h<BR>\n" );
document.write( "28mi/h speed of the faster bike.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );