document.write( "Question 29175: please illustrate the figure..The diagonals of a rhombus are 10 and 24.
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document.write( "(a) Find a side of the rhombus
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document.write( "(b) find the altitude of the rhombus
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Algebra.Com's Answer #16061 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! SEE THE FOLLOWING EXAMPLE AND TRY TO UNDERSTAND THE EXPLANATION. \n" ); document.write( "ANSWERS ARE \n" ); document.write( "SIDE=SQUARE ROOT OF ((10/2)^2+(24/2)^2)=13 \n" ); document.write( "ALTITUDE = AREA/SIDE \n" ); document.write( "AREA =(1/2)*D1*D2=10*24/2=120 \n" ); document.write( "ALTITUDE=120/13=9.2 \n" ); document.write( "----------------------------------------------------------------- \n" ); document.write( "IN A RHOMBUS IF SIDE IS X WE HAVE \n" ); document.write( "(D1/2)^2+(D2/2)^2=X^2...WHERE D1 AND D2 ARE DIAGONALS \n" ); document.write( "IF D1=X = 6=AB=BC=CD=DA.....GIVEN.....THEN \n" ); document.write( "(X/2)^2+(D2/2)^2=X^2... \n" ); document.write( "(D2/2)^2=3X^2/4 \n" ); document.write( "D2/2=X*SQRT3/2 \n" ); document.write( "D2=X*SQRT3 \n" ); document.write( "SO EACH DIAGONAL IS X AND X*SQRT(3) \n" ); document.write( "NOW X=6 SO \n" ); document.write( "D1=6=AC AND D2 =6SQRT(3)=10.4 =BD\r \n" ); document.write( "\n" ); document.write( "FIGURE IS GIVEN BELOW...DIMENSIONS ARE NOT THE SAME AS THOSE OF GIVEN RHOMBUS. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |