document.write( "Question 212693This question is from textbook
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document.write( ": distance,speed, and time.
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document.write( "It took a crew 2 hours and 40mins. to row 6km upstream and back again. If the rate of flow of the stream was 3km/hr, what was the rowing speed of the crew in still water? \n" );
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Algebra.Com's Answer #160604 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! distance,speed, and time. \n" ); document.write( "It took a crew 2 hours and 40mins. to row 6km upstream and back again. If the rate of flow of the stream was 3km/hr, what was the rowing speed of the crew in still water? \n" ); document.write( "------------------------ \n" ); document.write( "Upstream DATA: \n" ); document.write( "distance = 6 km ; rate = b-3 km ; time = 6/(b-3) hrs \n" ); document.write( "---------------------------- \n" ); document.write( "Downstream DATA: \n" ); document.write( "distance = 6 km ; rate = b+3 km ; time = 6/(b+3) hrs \n" ); document.write( "------------------------------- \n" ); document.write( "Equation: \n" ); document.write( "time + time = 2 2/3 hrs \n" ); document.write( "--- \n" ); document.write( "6/(b-3) + 6/(b+3) = 8/3 hrs \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 3(b-3)(b+3) to get: \n" ); document.write( "6*3(b+3) + 6*3(b-3) = 8(b^2-9) \n" ); document.write( "18b + 18b = 8b^2 - 72 \n" ); document.write( "8b^2 - 36b - 72 = 0 \n" ); document.write( "2b^2 - 9b - 18 = 0 \n" ); document.write( "(b-6)(2b+3) = 0 \n" ); document.write( "--- \n" ); document.write( "Positive solution: \n" ); document.write( "b = 6 km (speed of the boat in still water) \n" ); document.write( "============================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |