document.write( "Question 212519: Solve each equation\r
\n" ); document.write( "\n" ); document.write( " 3/x-2 + 1/x+2 =12/x2 - 4\r
\n" ); document.write( "\n" ); document.write( "I know that I need to find a common denominator and to reduce the x squared would be:
\n" ); document.write( " 3/X-2 + 1/X+2 = 12/(x+2)(x-2)
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\n" ); document.write( "This is where I get confused.\r
\n" ); document.write( "\n" ); document.write( "The common denominator is x + 2 \r
\n" ); document.write( "\n" ); document.write( "3 (x+2) + 1 (x-2) = 12\r
\n" ); document.write( "\n" ); document.write( "3x + 6 + 1x - 2 = 12\r
\n" ); document.write( "\n" ); document.write( "4x - 4 - 12 = 0\r
\n" ); document.write( "\n" ); document.write( "(2x - 3) (2x +4) = 0
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Algebra.Com's Answer #160599 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Solve each equation
\n" ); document.write( "3/(x-2) + 1/(x+2) =12/(x^2 - 4)
\n" ); document.write( "----------------------------------------
\n" ); document.write( "Multiply thru by (x^2-4) which is (x-2)(x+2)
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\n" ); document.write( "3(x+2) + (x-2) = 12
\n" ); document.write( "3x+6 + x-2 = 12
\n" ); document.write( "4x+4 = 12
\n" ); document.write( "x+1 = 3
\n" ); document.write( "x = 2
\n" ); document.write( "----
\n" ); document.write( "But x cannot be 2 because of the denominator x-2
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\n" ); document.write( "Answer: No solution
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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