document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29178>Question 29178</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please illustrate the figure..the longer base of an isosceles trapezoid is 40, one leg is 20 and one of the base angles is 63 degrees.<BR>\n" );
document.write( "(a) find the altitude and shorter base of the trapezoid<BR>\n" );
document.write( "(b) using the results obtained in (a), find the area of the trapezoid<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #16053 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=16053\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SEE THE TRAPEZOID ....ABCD below<BR>\n" );
document.write( "AREA OF TRAPEZOID IS GIVEN BY <BR>\n" );
document.write( "AREA=(1/2)*ALTITUDE*(SUM OF PARALLEL SIDES)=(1/2)*DP*(AB+CD)<BR>\n" );
document.write( "WHERE ALTITUDE IS THE PERPENDICULAR DISTANCE BETWEEN PARALLEL SIDES =DP<BR>\n" );
document.write( "PARALLEL SIDES ARE AB AND CD.<BR>\n" );
document.write( "WE HAVE AB=40<BR>\n" );
document.write( "BC=AD=20<BR>\n" );
document.write( "ANGLE DAP=63<BR>\n" );
document.write( "DAP IS A RIGHT ANGLED TRIANGLE...DP/DA=SIN(63)<BR>\n" );
document.write( "DP=DA*SIN(63)=20*0.89=17.8<BR>\n" );
document.write( "SO ALTITUDE=17.8<BR>\n" );
document.write( "AP/DA=COS(63)<BR>\n" );
document.write( "AP=DA*COS(63)=20*0.4545=9.1<BR>\n" );
document.write( "SO CD =AB-2*AP SINCE TRAPEZOID IS ISOCELLES..<BR>\n" );
document.write( "CD=40-2*9.1=21.8<BR>\n" );
document.write( "AREA=(1/2)17.8(40+21.8)=550 SQUARE UNITS.<BR>\n" );
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