document.write( "Question 212539: Using the addition method, what is the solution to 2x-5y=4 and 7x-2y=4 \r
\n" ); document.write( "\n" ); document.write( "I've tried and I can't figure it out. I eliminate the x's by multiplying to 14 but i get the fraction of 16/31y and it isn't correct.
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Algebra.Com's Answer #160511 by stanbon(75887)\"\" \"About 
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Using the addition method, what is the solution to
\n" ); document.write( "2x-5y=4
\n" ); document.write( "7x-2y=4
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\n" ); document.write( "Multiply thru the 1st equation by 2; Multiply thru the 2nd equation by 5.
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\n" ); document.write( "4x-10y = 8
\n" ); document.write( "35x-10y = 20
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\n" ); document.write( "Subtract the 1st from the 2nd to solve for \"x\":
\n" ); document.write( "31x = 12
\n" ); document.write( "x = 12/31
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\n" ); document.write( "Substitute into 2x-5y=4 to solve for \"y\":
\n" ); document.write( "2(12/31) - 5y = 4
\n" ); document.write( "24/31 - 5y = 124/31
\n" ); document.write( "5y = -100/31
\n" ); document.write( "y = -20/31
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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