document.write( "Question 212518: need help to find the equation of the line which contains the point(2,1) and has slope 2 \n" ); document.write( "
Algebra.Com's Answer #160494 by drj(1380)\"\" \"About 
You can put this solution on YOUR website!
Need help to find the equation of the line which contains the point(2,1) and has slope 2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 1. The slope m is given as\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"m=%28y2-y1%29%2F%28x2-x1%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 2. Let (x1,y1)=(2,1) or x1=2 and y1=1 . Let other point be ((x2,y2)=(x,y) or x2=x and y2=y.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 3. Now we're given \"m=2\". Substituting above values and variables in the slope equation m yields the following steps:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"m=%28y2-y1%29%2F%28x2-x1%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2=%28y-1%29%2F%28x-2%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 4. Multiply x-2 to both sides to get rid of denominator on right side of equation.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%28x-2%29=y-1\" \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2x-4=y-1\" \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Step 5. Now add 1 to both sides of equation to solve for y.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2x-4%2B1=y-1%2B1\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2x-3=y\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Note: the above equation can be rewritten as \r
\n" ); document.write( "\n" ); document.write( "\"2x-y=3\"\r
\n" ); document.write( "\n" ); document.write( "And the graph is shown below which is consistent with the above steps.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"2+x+%2B+-1+y+=+3\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+-2%2F-1\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 3/2 = 1.5.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 3/-1 = -3.
  • Slope is -2/-1 = 2.
  • Equation in slope-intercept form: y=2*x+-3.
\"graph%28+500%2C+500%2C+1.5-8%2C+1.5%2B8%2C+-3-8%2C+-3%2B8%2C+2%2Ax%2B-3+%29+\"\n" ); document.write( "

\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful. Good luck in your studies!\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );