document.write( "Question 212520: need help to find the equation of the line which contains the point (5,-2)and has slope negative two fifths.\r
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Algebra.Com's Answer #160486 by drj(1380)\"\" \"About 
You can put this solution on YOUR website!
Need help to find the equation of the line which contains the point (5,-2)and has slope negative two fifths.\r
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\n" ); document.write( "\n" ); document.write( "Step 1. The slope m is given as\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y2-y1%29%2F%28x2-x1%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Let (x1,y1)=(5,-2) or x1=5 and y1=-2 . Let other point be ((x2,y2)=(x,y) or x2=x and y2=y.\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Now we're given \"m=-2%2F5\". Substituting above values and variables in the slope equation m yields the following steps:\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y2-y1%29%2F%28x2-x1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"-2%2F5=%28y-%28-2%29%29%2F%28x-5%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"-2%2F5=%28y%2B2%29%2F%28x-5%29\"\r
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\n" ); document.write( "\n" ); document.write( "Step 4. Multiply x-5 to both sides to get rid of denominator on right side of equation.\r
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\n" ); document.write( "\n" ); document.write( "\"%28-2%2F5%29%28x-5%29=y%2B2\" \r
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\n" ); document.write( "\n" ); document.write( "Step 5. Now multiply 5 to both sides of equation to get rid of denominator on left side of equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-2%28x-5%29=5%28y%2B2%29\" \r
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\n" ); document.write( "\n" ); document.write( "Step 6. Now multiply everything out and solve for y\r
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\n" ); document.write( "\n" ); document.write( "\"-2x%2B10=5y%2B10\"\r
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\n" ); document.write( "\n" ); document.write( "Subtract 10 from both sides to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"-2x%2B10-10=5y%2B10-10\"\r
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\n" ); document.write( "\n" ); document.write( "\"-2x=5y\"\r
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\n" ); document.write( "\n" ); document.write( "Divide by 5 to get y\r
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\n" ); document.write( "\n" ); document.write( "\"5y%2F5=-2x%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=-2x%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "Note: the above equation can be rewritten as \r
\n" ); document.write( "\n" ); document.write( "\"5y%2B2x=0\"\r
\n" ); document.write( "\n" ); document.write( "And the graph is shown below which is consistent with the above steps.\r
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"2+x+%2B+5+y+=+0\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+-2%2F5\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 0/2 = 0.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 0/5 = 0.
  • Slope is -2/5 = -0.4.
  • Equation in slope-intercept form: y=-0.4*x+0.
\"graph%28+500%2C+500%2C+0-8%2C+0%2B8%2C+0-8%2C+0%2B8%2C+-0.4%2Ax%2B0+%29+\"\n" ); document.write( "

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\n" ); document.write( "\n" ); document.write( "I hope the above steps were helpful. Good luck in your studies!\r
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\n" ); document.write( "\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J\r
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\n" ); document.write( "\n" ); document.write( "For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra.\r
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