document.write( "Question 212405: Find two consecutive odd integers such that 3 times the first is 5 more than twice the second\r
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Algebra.Com's Answer #160433 by drj(1380)\"\" \"About 
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Find two consecutive odd integers such that 3 times the first is 5 more than twice the second\r
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\n" ); document.write( "\n" ); document.write( "Step 1. Let n be one odd integer.\r
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\n" ); document.write( "\n" ); document.write( "Step 2. Let n+2 be the next odd integer.\r
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\n" ); document.write( "\n" ); document.write( "Step 3. Generate an equation for the given problem statement: Find two consecutive odd integers such that 3 times the first IS 5 more than twice the second. 3n is one side of equation and 5+2(n+2) is the opposite side of equation. \"is\" in the given problem statement implies \"equal to\" so\r
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\n" ); document.write( "\n" ); document.write( "\"3n+=+5%2B2%28n%2B2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"3n+=+5%2B2n%2B4\"\r
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\n" ); document.write( "\n" ); document.write( "Step 4. Solve for n. Subtract 2n from both sides of equation.\r
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\n" ); document.write( "\n" ); document.write( "\"3n-2n+=+5%2B2n%2B4-2n\"\r
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\n" ); document.write( "\n" ); document.write( "\"n+=+9\"\r
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\n" ); document.write( "\n" ); document.write( "\"n%2B2+=+11\"\r
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\n" ); document.write( "\n" ); document.write( "Check numbers with problem statement. \r
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\n" ); document.write( "\n" ); document.write( "\"3%28n%29=3%289%29=27\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%28n%2B2%29=2%2811%29=22\" so 27 is 5 more than twice 11. So numbers are odd and satisfies problem statement.\r
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\n" ); document.write( "\n" ); document.write( "Step 5. ANSWER: Numbers are 9 and 11.\r
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\n" ); document.write( "\n" ); document.write( "Hope the steps were helpful. Good luck in your studies.
\n" ); document.write( "Respectfully,
\n" ); document.write( "Dr J\r
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\n" ); document.write( "\n" ); document.write( "For Step-By-Step videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra.\r
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