document.write( "Question 212320: HOW MANY LITERS OF A 10% ALCOHOL SOLUTION MUST BE MIXED WITH 40 L OF A 50% SOLUTION TO GET A 40% SOLUTION? \n" ); document.write( "
Algebra.Com's Answer #160391 by HyperBrain(694)\"\" \"About 
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Let x=the amount of 10% alcohol solution required
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\n" ); document.write( "x L + 40 L = (x+40) L of mixture
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\n" ); document.write( "If we have x L of 10% alcohol solution, we have 0.10x L pure alcohol
\n" ); document.write( "If we have 40 L of 50% alcohol solution, we have 0.5(40)=20 L pure alcohol
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\n" ); document.write( "So, we have the equation:
\n" ); document.write( "0.40(x+40)=0.10x+20
\n" ); document.write( "40(x+40)=10x+2000
\n" ); document.write( "4(x+40)=x+200
\n" ); document.write( "4x+160=x+200
\n" ); document.write( "3x=40
\n" ); document.write( "x=40/3 L
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