document.write( "Question 212317: you and your brother started biking at noon from places that are 52 miles apart. You rode toward eachother and met at 2:00 p.m. Your brother's average speed was 4 mi/h faster than your average speed. Find both speeds. So how do i begin this problem, i dont know what to do. \n" ); document.write( "
Algebra.Com's Answer #160341 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "lET X & (X=4) BE THE 2 SPEEDS.
\n" ); document.write( "52=(X+X+4)*2
\n" ); document.write( "52=(2X+4)*2
\n" ); document.write( "52=4X+8
\n" ); document.write( "4X=52-8
\n" ); document.write( "4X=44
\n" ); document.write( "X=44/4
\n" ); document.write( "X=11 MPH FOR THE SLOWER RIDER.
\n" ); document.write( "11+4=15 MPH FOR THE FASTER RIDER.
\n" ); document.write( "PROOF:
\n" ); document.write( "52=(11+15)*2
\n" ); document.write( "52=26*2
\n" ); document.write( "52=52
\n" ); document.write( "
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