document.write( "Question 212317: you and your brother started biking at noon from places that are 52 miles apart. You rode toward eachother and met at 2:00 p.m. Your brother's average speed was 4 mi/h faster than your average speed. Find both speeds. So how do i begin this problem, i dont know what to do. \n" ); document.write( "
Algebra.Com's Answer #160341 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "lET X & (X=4) BE THE 2 SPEEDS. \n" ); document.write( "52=(X+X+4)*2 \n" ); document.write( "52=(2X+4)*2 \n" ); document.write( "52=4X+8 \n" ); document.write( "4X=52-8 \n" ); document.write( "4X=44 \n" ); document.write( "X=44/4 \n" ); document.write( "X=11 MPH FOR THE SLOWER RIDER. \n" ); document.write( "11+4=15 MPH FOR THE FASTER RIDER. \n" ); document.write( "PROOF: \n" ); document.write( "52=(11+15)*2 \n" ); document.write( "52=26*2 \n" ); document.write( "52=52 \n" ); document.write( " \n" ); document.write( " |