document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=3591>Question 3591</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a question that is driving my wife and I crazy.  Can you help us figure it out.  It goes something like this:<BR>\n" );
document.write( "Leah is 5 yrs older than Sue.  John is 6 yrs older than Leah.  Their ages total equals 41.  How old is Sue?  What is the equation for this problem?  Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1603 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1603\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this has 2 unknowns, so you will need 2 equations.\r<BR>\n" );
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document.write( "First define a couple of things:<BR>\n" );
document.write( "Let x = Leah's age now<BR>\n" );
document.write( "Let y = Sue's age now\r<BR>\n" );
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document.write( "eqn1: x = y+5 --> x-y = 5\r<BR>\n" );
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document.write( "eqn2: x+y = 41\r<BR>\n" );
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document.write( "Adding these 2 equations together gives 2x = 46, so x (Leah's age) = 23. Hence, Sue must be 18.\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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