document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=212205>Question 212205</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321442547/algebrahomeworkh>Algebra For College Students</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Johnny leaves Memphis to visit Anne, who lives in Hornsby, TN, 80 miles away. He travels at an average speed of 50 mph. One-half hour later, Anne leaves to visit Johnny, traveling at an average speed of 60 mph. How long after Anne leaves will it be before they meet?\r<BR>\n" );
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document.write( "I have tried to work this a few ways and I know that due to Johnny's speed of 50 mph, he gets 25 miles closer to Anne in the half hour he is traveling before she starts. After that I am lost.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #160275 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=160275\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Johnny leaves Memphis to visit Anne, who lives in Hornsby, TN, 80 miles away.<BR>\n" );
document.write( " He travels at an average speed of 50 mph. One-half hour later, <BR>\n" );
document.write( "Anne leaves to visit Johnny, traveling at an average speed of 60 mph.<BR>\n" );
document.write( " How long after Anne leaves will it be before they meet?<BR>\n" );
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document.write( "Let t = Anne's travel time<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(t+.5) = John's travel time (half hour longer the Anne)<BR>\n" );
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document.write( "When they meet, they will have traveled a total of 80 mi<BR>\n" );
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document.write( "Write a distance equation: Dist = speed * time<BR>\n" );
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document.write( "J's dist + A's dist = 80 mi<BR>\n" );
document.write( "50(t+.5) + 60t = 80<BR>\n" );
document.write( "50t + 25 + 60t = 80<BR>\n" );
document.write( "50t + 60t = 80 - 25<BR>\n" );
document.write( "110t = 55<BR>\n" );
document.write( "t = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=55%2F110 ALIGN=MIDDLE  ALT=\"55%2F110\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "t = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F2 ALIGN=MIDDLE  ALT=\"1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > hr is A's travel time<BR>\n" );
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document.write( "Check solution by finding the total dist:<BR>\n" );
document.write( "60*.5 = 30<BR>\n" );
document.write( "50*(.5+.5) = 50 mi<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "total dist 80 mi </SPAN>\n" );
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