document.write( "Question 212195: The period (the time required for one complete swing) of a simple pendulum varies directly as the square root of its length. If a pedulum 12 feet long has a period of 4 seconds, find the period of a pendulum 3 feet long. \n" ); document.write( "
Algebra.Com's Answer #160262 by Fombitz(32388)\"\" \"About 
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\"P=k%2Asqrt%28L%29\", where k is a constant.
\n" ); document.write( "\"P%5E2=KL\"
\n" ); document.write( "\"K=P%5E2%2FL\"
\n" ); document.write( "\"%28P1%29%5E2%2FL1=%28P2%29%5E2%2FL2\"
\n" ); document.write( "\"4%5E2%2F12=%28P2%29%5E2%2F3\"
\n" ); document.write( "\"%28P2%29%5E2=%284%5E2%2A3%29%2F12\"
\n" ); document.write( "\"P2=4%2Asqrt%283%2F12%29=4%2A%281%2F2%29=2\"
\n" ); document.write( "The period is 2 seconds.
\n" ); document.write( "
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