document.write( "Question 212042: Diego is twice as old as Anna now. Six years ago, Diego was triple Anna's age. Find both their present ages please. \n" ); document.write( "
Algebra.Com's Answer #160231 by ankor@dixie-net.com(22740)\"\" \"About 
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Diego is twice as old as Anna now.
\n" ); document.write( "d = 2a
\n" ); document.write( ":
\n" ); document.write( "Six years ago, Diego was triple Anna's age.
\n" ); document.write( "d - 6 = 3(a-6)
\n" ); document.write( "d - 6 = 3a - 18
\n" ); document.write( "d = 3a - 18 + 6
\n" ); document.write( "d = 3a - 12
\n" ); document.write( ":
\n" ); document.write( "Find both their present ages please.
\n" ); document.write( ":
\n" ); document.write( "Substitute 2a for d in the above equation:
\n" ); document.write( "2a = 3a - 12
\n" ); document.write( "2a - 3a = -12
\n" ); document.write( "-a = -12
\n" ); document.write( "a = 12 is Anna's present age
\n" ); document.write( "then
\n" ); document.write( "2(12) = 24 is D's present age
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution in the statement:
\n" ); document.write( "\"Six years ago, Diego was triple Anna's age.\"
\n" ); document.write( "24 - 6 = 3(12-6)
\n" ); document.write( "18 = 3(6) \n" ); document.write( "
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