document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=212095>Question 212095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what 2 digit number is equal to twice the product of it's digits? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #160204 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=160204\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the number be <BR>\n" );
document.write( "A*10+B where A and B are between 0 and 9<BR>\n" );
document.write( "A*10+B=2(AB)<BR>\n" );
document.write( "10+(B/A)=2B<BR>\n" );
document.write( "B and A must be multiples of each other for this equation to work. <BR>\n" );
document.write( "(2,4) and (3,6) are the only digits that are multiples.<BR>\n" );
document.write( "10+(4/2)=2(4)<BR>\n" );
document.write( "12=8<BR>\n" );
document.write( "No, that doesn't work.<BR>\n" );
document.write( "10+(6/3)=2(6)<BR>\n" );
document.write( "12=12<BR>\n" );
document.write( "Yes, that works.<BR>\n" );
document.write( "The number is 36. <BR>\n" );
document.write( "36=2*(3*6)=36<BR>\n" );
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document.write( "The other possible solution is 00, because<BR>\n" );
document.write( "00=2(0*0)<BR>\n" );
document.write( "although I'm not sure that 0 is really a 2 digit number.  </SPAN>\n" );
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