document.write( "Question 212101: Dear Tutor,\r
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document.write( "I would like to know how can I arrive/make:
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document.write( "y*z*(z-y)+x*y*(y-x)+x*z*(x-z) \r
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document.write( "into\r
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document.write( "(x-y)*(y-z)*(z-x)\r
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document.write( "I have tried multiplying all factors also tried to divide by factor:y and than factor:z but that's where I got stuck so I'm not sure if I'm even close to the right method.\r
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document.write( "Thank you for your time and effort,\r
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document.write( "Gabi \n" );
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Algebra.Com's Answer #160183 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "This is a tough one. For one, you have to be good at factoring by grouping. Another key is recognizing that: \n" ); document.write( "z-y = -1(y-z) \n" ); document.write( "y-x = -1(x-y) \n" ); document.write( "x-z = -1(z-x) \n" ); document.write( "Substituting the first of these into the original we get: \n" ); document.write( " \n" ); document.write( "Now we have one of the desired factors, (y-z), present. The rest is manipulations with the goal of having (y-z) as a common factor. First we'll multiply out the reset of the expression: \n" ); document.write( " \n" ); document.write( "Rearranging the terms for factoring by grouping we get: \n" ); document.write( " \n" ); document.write( "Factoring x from the \"red\" terms and \n" ); document.write( " \n" ); document.write( "Factoring the \"red\" expression as a difference of squares we get: \n" ); document.write( " \n" ); document.write( "Now we have (y-z) as a common factor of each term. We can factor it out: \n" ); document.write( " \n" ); document.write( "Multiplying out the \"red\" expression we get: \n" ); document.write( " \n" ); document.write( "Rearranging the terms for factoring by grouping we get: \n" ); document.write( " \n" ); document.write( "Factoring z from the \"red\" terms and -x from the \"green\" terms we get: \n" ); document.write( " \n" ); document.write( "Now we can factor the (x-y)'s: \n" ); document.write( " \n" ); document.write( "With the Associative Property we can remove the extra parentheses giving: \n" ); document.write( " \n" ); document.write( "And with the Commutative Property we have: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and we're done! \n" ); document.write( " |