document.write( "Question 212067: how many quarts of pure antifreeze must be added to 5 quarts of 10% antifreeze solution to obtain a 30% antifreeze solution \n" ); document.write( "
Algebra.Com's Answer #160168 by HyperBrain(694)\"\" \"About 
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Let x=the amount of pure antifreeze required
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\n" ); document.write( "If we add x quarts to 5 liters, we get x+5 quarts.
\n" ); document.write( "For x quarts of pure antifreeze, we have x quarts of antifreeze.
\n" ); document.write( "For 5 quarts of 10% antifreeze, we have (0.1)(5 quarts)=0.5 quart of antifreeze
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\n" ); document.write( "So, we have the equation,
\n" ); document.write( "0.3(x+5)=x+0.5
\n" ); document.write( "0.3x+1.5=x+0.5
\n" ); document.write( "0.7x=1
\n" ); document.write( "7x=10
\n" ); document.write( "x=10/7 quarts
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