document.write( "Question 212012: How long will it take a sample of radioactive substance to decay half of its original amount, if it decays according to the function A(t) = 450e^-0.249t , where t is the time in years? Round to the nearest hundreth year.\r
\n" ); document.write( "\n" ); document.write( "choices (in years):
\n" ); document.write( "2.78
\n" ); document.write( "112.05
\n" ); document.write( "24.54
\n" ); document.write( "27.32
\n" ); document.write( "

Algebra.Com's Answer #160131 by ankor@dixie-net.com(22740)\"\" \"About 
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How long will it take a sample of radioactive substance to decay half of its
\n" ); document.write( " original amount, if it decays according to the function
\n" ); document.write( "A(t) = 450e^-0.249t , where t is the time in years?
\n" ); document.write( "Round to the nearest hundredth year.
\n" ); document.write( ":
\n" ); document.write( "Half of original amt: 450/2 = 225 [A(t)]
\n" ); document.write( ":
\n" ); document.write( "\"450%2Ae%5E%28-.249t%29\" = 225
\n" ); document.write( "divide both sides by 450
\n" ); document.write( "\"e%5E%28-.249t%29\" = \"225%2F450\"
\n" ); document.write( "\"e%5E%28-.249t%29\" = .5
\n" ); document.write( "then log equiv of exponents
\n" ); document.write( "-.249t*ln(e) = ln(.5)
\n" ); document.write( "ln of e is one so we have:
\n" ); document.write( "-.249t = -.693
\n" ); document.write( "t = \"%28-.693%29%2F%28-.249%29\"
\n" ); document.write( "t = 2.78 yrs
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution on a calc; enter: 450*e^(-.249*2.78)= 225.2 half the original amt
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