document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=212034>Question 212034</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive positive odd integers such that 4 times the sum of all three equals 13 more than the product of the smaller two. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #160123 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=160123\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Find three consecutive positive odd integers such that 4 times the sum of all three equals 13 more than the product of the smaller two.<BR>\n" );
document.write( "--------------------------------------------------------------<BR>\n" );
document.write( "1st: 2x-1<BR>\n" );
document.write( "2nd: 2x+1<BR>\n" );
document.write( "3rd: 2x+3<BR>\n" );
document.write( "================<BR>\n" );
document.write( "Eequation:<BR>\n" );
document.write( "4(6x+3) = (2x-1)(2x+1) + 13<BR>\n" );
document.write( "24x+12 = 4x^2-1 + 13<BR>\n" );
document.write( "4x^2 -24x = 0<BR>\n" );
document.write( "4x(x-6) = 0<BR>\n" );
document.write( "x = 0 or x = 6<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Positive solutions:<BR>\n" );
document.write( "1st 2x-1 = 2*6-1 = 11<BR>\n" );
document.write( "2nd : 13<BR>\n" );
document.write( "4rd : 15<BR>\n" );
document.write( "=======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );