document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=212009>Question 212009</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Due to evaporation, the volume of liquid in a beaker decreased by 20 percent every hour.  If the volume of liquid in a beaker was initially m cubic centimeters, what was the volume of the liquid in the beaker after 3 hours? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #160111 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=160111\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Due to evaporation, the volume of liquid in a beaker decreased by 20 percent every hour. If the volume of liquid in a beaker was initially m cubic centimeters, what was the volume of the liquid in the beaker after 3 hours?<BR>\n" );
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document.write( "After each hour, 80% remains of what there was an hour ago.<BR>\n" );
document.write( "After 3 hours, that's<BR>\n" );
document.write( "m*0.8*0.8*0.8<BR>\n" );
document.write( " = m (0.8^3)<BR>\n" );
document.write( "= 0.512m cc<BR>\n" );
document.write( " </SPAN>\n" );
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