document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=211911>Question 211911</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you create a triangle with the following measurements: 6\", 5\" and 12\"? What rule can you discover about the sides of a triangle?\r<BR>\n" );
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document.write( "I tried drawing a triangle with these measurements and have determined that it is not possible.  Having trouble explaining what the rule would be. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #160095 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10559)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=160095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A triangle can ONLY be possible if the DIFFERENCE between 2 of its sides is greater than the 3rd side, AND ALSO less than their sum. \r<BR>\n" );
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document.write( "In this case, 6, 5, and 12:\r<BR>\n" );
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document.write( "Let's take the 2 sides, 6 & 5. The 3rd side, 12, is supposed to be greater than the other 2 sides' difference of 1, which IT IS (12 > 6 - 5). Therefore, this is okay. However, the 3rd side, 12, is ALSO supposed to be less than the sum of the other 2 sides, which IT IS NOT. In other words, 12 should be less than (6 + 5), but is not. Instead, 12 > (6 + 5).\r<BR>\n" );
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document.write( "Let's now try the 2 sides, 5 & 12. The 3rd side, 6, is supposed to be greater than the other 2 sides' difference of 7, which IT IS NOT (6 not > 12 - 5). However, the 3rd side, 6, is ALSO supposed to be less than the sum of the other 2 sides, which IT IS. In other words, (6 < 12 + 5).\r<BR>\n" );
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document.write( "As seen, 1 of the rules does apply in all cases, but BOTH NEVER APPLY. BOTH need to apply in order for a triangle to be constructed with the given sides.\r<BR>\n" );
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document.write( "If you should take any other 2 sides and apply the same rules, both rules WILL NOT BE SATISFIED. Therefore, a triangle with sides 5, 6, and 12 IS NOT POSSIBLE. </SPAN>\n" );
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