document.write( "Question 211831This question is from textbook Introductory Algebra
\n" );
document.write( ": evaluate the discriminate b^2-4ac, then use the answer to state how many real-number solutions exist for the equation y=x^2+8x+16 \n" );
document.write( "
Algebra.Com's Answer #160039 by Theo(13342)![]() ![]() You can put this solution on YOUR website! your equation is y=x^2+8x+16 \n" ); document.write( "----- \n" ); document.write( "this is in the standard form of the equation. \n" ); document.write( "you find the roots when you set y = 0 and solve. \n" ); document.write( "your equation becomes: \n" ); document.write( "x^2 + 8x + 16 = 0 \n" ); document.write( "----- \n" ); document.write( "to find the roots using the quadratic formula, you would get the coefficients and plug them into that equation. \n" ); document.write( "----- \n" ); document.write( "standard form of a quadratic equation is: \n" ); document.write( "ax^2 + bx + c = 0 \n" ); document.write( "your equation makes: \n" ); document.write( "a = 1 \n" ); document.write( "b = 8 \n" ); document.write( "c = 16 \n" ); document.write( "----- \n" ); document.write( "the discriminant in this equation is b^-4ac \n" ); document.write( "----- \n" ); document.write( "if b^2-4ac = 0, then you have one real root. \n" ); document.write( "if b^2-4ac = positive you have two real roots. \n" ); document.write( "if b^2-4ac = positive and a perfect square you have two real integer roots. This assumes that a and c are also integers. \n" ); document.write( "if b^2-4ac = negative you have two imaginary roots. \n" ); document.write( "----- \n" ); document.write( "imaginary root means your graph does not cross the x-axis. \n" ); document.write( "it is either above it or below it but never crosses it. \n" ); document.write( "it would be above it if the x^2 portion of your equation is positive. \n" ); document.write( "it would be below it if the x^2 portion of your equation is negative. \n" ); document.write( "----- \n" ); document.write( "b^2-4ac = (8^2 - 4*1*16) = 64 - 64 = 0 \n" ); document.write( "your equation will have one root. \n" ); document.write( "----- \n" ); document.write( "the quadratic formula says that this root will be at -8 +/- sqrt(0)/2 which makes it at -4. \n" ); document.write( "----- \n" ); document.write( "graph of your equation is shown below: \n" ); document.write( "----- \n" ); document.write( " \n" ); document.write( "----- \n" ); document.write( "you have one root at x = -4. \n" ); document.write( " \n" ); document.write( " |