document.write( "Question 211813: determine the linear velocity of a point rotating at 25 revolutions per minute at a distance of 2 feet from the center of the rotating object.\r
\n" ); document.write( "\n" ); document.write( "a)2.6 ft/sec\r
\n" ); document.write( "\n" ); document.write( "b)314.2 ft/sec\r
\n" ); document.write( "\n" ); document.write( "c)5.2 ft/sec\r
\n" ); document.write( "\n" ); document.write( "d)78.5 ft/sec \n" ); document.write( "

Algebra.Com's Answer #160035 by Earlsdon(6294) $\"\"$ $\"About$

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A point on the circumference of a circle of radius = 2ft. rotating at 25 rpm would have a linear velocity of:
\n" ); document.write( " $\"25%2A2%28pi%29%28r%29+=+50%2A%28pi%29%2A%28r%29\"$ Substitute $\"r+=+2\"$ and $\"pi+=+3.142\"$ , then the linear velocity would be:
\n" ); document.write( " $\"v%5Bl%5D+=+25%2A2%283.142%29%2A2\"$
\n" ); document.write( " $\"V%5Bl%5D+=+314.2\"$ ft.per sec. \n" ); document.write( "

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