document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=211783>Question 211783</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man is 32 years old and his son is 7 years old.  In how many years will the father be twice as old as his son? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #160017 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=160017\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 32+x=2(7+x)<BR>\n" );
document.write( "32+x=14+2x<BR>\n" );
document.write( "x-2x=14-32<BR>\n" );
document.write( "-x=-18<BR>\n" );
document.write( "x=18 <BR>\n" );
document.write( "In 18 years dad will be twicw as old as his son.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "32+18=2(7+18)<BR>\n" );
document.write( "50=2*25<BR>\n" );
document.write( "50=50<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );