document.write( "Question 211668: A cubic shipping container had a volume of v^3 cubic meters. The height of the container was decreased by a whole number of meters and the width was increased by a whole number of meters so that the volume of the container is now v^3+2v^2-3v. Find out the following:\r
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document.write( "a. By how many meters the height was decreased?\r
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document.write( "b. By how many meters the width was increased
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Algebra.Com's Answer #160004 by Theo(13342) You can put this solution on YOUR website! If it was a cubic shipping container, then it was a perfect cube making the dimensions of each side = v. \n" ); document.write( "----- \n" ); document.write( "original volume = v*v*v = v^3 \n" ); document.write( "----- \n" ); document.write( "The height was decreased by an integer called a. \n" ); document.write( "The width was increased by an integer called b. \n" ); document.write( "----- \n" ); document.write( "new volume = \n" ); document.write( "(v-a)*(v-b)*v = v^3 + 2v^2 - 3v \n" ); document.write( "----- \n" ); document.write( "If we divide both sides of this equation by v, we get: \n" ); document.write( "(v-a)*(v+b) = v^2 + 2v - 3 \n" ); document.write( "----- \n" ); document.write( "if we factor the equation on the right side, we get: \n" ); document.write( "(v-a)*(v+b) = (v-1)*(v+3) \n" ); document.write( "----- \n" ); document.write( "This means that a = 1 and b = 3 will satisfy the equation. \n" ); document.write( "----- \n" ); document.write( "The height is reduced by 1 and the width is increased by 2. \n" ); document.write( "v*v*v = v^3 \n" ); document.write( "(v-1)*(v+3)*v = v^3 + 2v^2 - 3v \n" ); document.write( "----- \n" ); document.write( "Answer is: \n" ); document.write( "height is reduced by 1 and width is increased by 3 meters. \n" ); document.write( "----- \n" ); document.write( " \n" ); document.write( " |