document.write( "Question 211668: A cubic shipping container had a volume of v^3 cubic meters. The height of the container was decreased by a whole number of meters and the width was increased by a whole number of meters so that the volume of the container is now v^3+2v^2-3v. Find out the following:\r
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\n" ); document.write( "\n" ); document.write( "b. By how many meters the width was increased
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Algebra.Com's Answer #160004 by Theo(13342)\"\" \"About 
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If it was a cubic shipping container, then it was a perfect cube making the dimensions of each side = v.
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\n" ); document.write( "original volume = v*v*v = v^3
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\n" ); document.write( "The height was decreased by an integer called a.
\n" ); document.write( "The width was increased by an integer called b.
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\n" ); document.write( "new volume =
\n" ); document.write( "(v-a)*(v-b)*v = v^3 + 2v^2 - 3v
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\n" ); document.write( "If we divide both sides of this equation by v, we get:
\n" ); document.write( "(v-a)*(v+b) = v^2 + 2v - 3
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\n" ); document.write( "if we factor the equation on the right side, we get:
\n" ); document.write( "(v-a)*(v+b) = (v-1)*(v+3)
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\n" ); document.write( "This means that a = 1 and b = 3 will satisfy the equation.
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\n" ); document.write( "The height is reduced by 1 and the width is increased by 2.
\n" ); document.write( "v*v*v = v^3
\n" ); document.write( "(v-1)*(v+3)*v = v^3 + 2v^2 - 3v
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\n" ); document.write( "Answer is:
\n" ); document.write( "height is reduced by 1 and width is increased by 3 meters.
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