document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=211762>Question 211762</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/1592009425/algebrahomeworkh>COLLEGE ALGEBRA</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Pls help <BR>\n" );
document.write( "1/125, 1/25, 1/5.....to 7term\r<BR>\n" );
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document.write( "•	Write the next 3 terms,<BR>\n" );
document.write( "•	Find the indicated tn,<BR>\n" );
document.write( "•	Find the indicated Sn.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #160002 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=160002\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/125,1/25,1/5,......<BR>\n" );
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document.write( "appears  to  be  a  geometric  series, with  a  multiple  of (1/ 1/5) or 5<BR>\n" );
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document.write( "The  basic  form  is ,,,a(n) = a(1)r^(n-1),,with  a(1) = 1/125, and r=5<BR>\n" );
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document.write( "check,,,1st term,,,a(1) = 1/125 * 5^(1-1) = 1/125,,,,ok<BR>\n" );
document.write( ",,,,,,,,2 nd term,,a(2) = 1/125 * 5^(2-1) = 1/25,,,,ok<BR>\n" );
document.write( ",,,,,,,,3 rd term,,a(3) = 1/125 *5^(3-1) = 1/5,,,,,ok<BR>\n" );
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document.write( ",,,,,,,,4 th term ,,a(4) = 1/125 *5^(4-1)= 1<BR>\n" );
document.write( ",,,,,,,,5 th term,,,a(5) = 1/125 *5^(5-1) = 5<BR>\n" );
document.write( ",,,,,,,,6 th term ,,a(6) = 1/125 *5^(6-1) = 25<BR>\n" );
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document.write( ",,,,,,,,7 th term ,,a(7) = 1/125 * 5^(7-1) = 125,,,,,t(n)<BR>\n" );
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document.write( "The  sum  of  a  geometric  series  is,  S=a(1) [ (1-r^n) /(1-r) ]<BR>\n" );
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document.write( "In  this  case S(7) = (1/125) [ ( 1-5^7) / (1-5) ]<BR>\n" );
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document.write( "S(7) = (1/125) [ (-78124) / (-4)] <BR>\n" );
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document.write( "S(7) = (1/125) [ 19531]<BR>\n" );
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document.write( "s(7) = 156.248<BR>\n" );
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document.write( "check,,,adding  the  individual  terms  above = 156.248,,,,ok\r<BR>\n" );
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