document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=211684>Question 211684</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has perimeter of 100 feet. Express the area A of the rectangle as a function of x. In other words, find A(x). (Picture of rectangle with y as width and x as length). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #159952 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=159952\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A rectangle has perimeter of 100 feet. Express the area A of the rectangle as a function of x. In other words, find A(x). (Picture of rectangle with y as width and x as length).<BR>\n" );
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document.write( "Area = xy sq. units<BR>\n" );
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document.write( "Perimeter = 2(x+y)<BR>\n" );
document.write( "100 = 2(x+y)<BR>\n" );
document.write( "x+y = 50<BR>\n" );
document.write( "y = 50-x<BR>\n" );
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document.write( "Therefore Area = x(50-x) = 50x-x^2 sq. units<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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