document.write( "Question 210553This question is from textbook
\n" ); document.write( ": Tell whether each statment is true or false. Then write the converse and tell whether it is true or false.
\n" ); document.write( "If \"a%5E2%3E9\",then \"a%3E3\".\r
\n" ); document.write( "\n" ); document.write( "Note: I understand what the converse of this statement is, and I know the answer is false, but I cont comprehend why this converse would be false.
\n" ); document.write( "

Algebra.Com's Answer #159941 by engchunh(1)\"\" \"About 
You can put this solution on YOUR website!
Okay if \"a%5E2%3E9\"
\n" ); document.write( "then \"a%5E2-9%3E0\"
\n" ); document.write( "then (a-3)(a+3) > 0
\n" ); document.write( "therefore a<-3 AND a>3 \r
\n" ); document.write( "\n" ); document.write( "Therefore a>3 is NOT the only solution the other solution is a<-3.\r
\n" ); document.write( "\n" ); document.write( "CHUN
\n" ); document.write( "
\n" );