document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=211636>Question 211636</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a picture frame is 3 inches greater than the width. The perimeter is less than 52 inches. Describe the dimensions of the frame </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #159936 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=159936\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=W+3<BR>\n" );
document.write( "2L+2W<52<BR>\n" );
document.write( "2(W+3)+2W<52<BR>\n" );
document.write( "2W+6+2W<52<BR>\n" );
document.write( "4W<52-6<BR>\n" );
document.write( "4W<46<BR>\n" );
document.write( "W<46/4<BR>\n" );
document.write( "W<11.5 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "LET W=11<BR>\n" );
document.write( "2(11+3)+2*11<52<BR>\n" );
document.write( "2*14+22<52<BR>\n" );
document.write( "28+22<52<BR>\n" );
document.write( "50<52<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );