document.write( "Question 29140: Adult tickets for a play cost $15 and child tickets cost $1. If there were 29 people at a performance and the theater collected $155 from ticket sales, how many adults and how many children attended the play? \n" ); document.write( "
Algebra.Com's Answer #15993 by checkley72(6)\"\" \"About 
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$15.00 X Adults + $1.00 X Children = $ 155.00\r
\n" ); document.write( "\n" ); document.write( "Adults + Children = 29 Or (A + C = 29)\r
\n" ); document.write( "\n" ); document.write( "A + C = 29 C = 29 - A\r
\n" ); document.write( "\n" ); document.write( "Substituting C = 29 - A in the first equation & solving for A we get:\r
\n" ); document.write( "\n" ); document.write( "15A + 1(29 - A)= 155\r
\n" ); document.write( "\n" ); document.write( "15A + 29 - A = 155\r
\n" ); document.write( "\n" ); document.write( "15A - A = 155 - 29\r
\n" ); document.write( "\n" ); document.write( "14 A = 126\r
\n" ); document.write( "\n" ); document.write( "A = 126/14 or A = 9. \r
\n" ); document.write( "\n" ); document.write( "A + C = 29 or 9 + C = 29 or C = 29 - 9 or C = 20.\r
\n" ); document.write( "\n" ); document.write( "9 Adults @ $ 15.00 + 20 Children @ $ 1.00. $ 135.00 + $ 20.00 = $ 155.00\r
\n" ); document.write( "\n" ); document.write( "9 Adults + 20 Children = 29 people attending the play.\r
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